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4x^2-12x-1147=0
a = 4; b = -12; c = -1147;
Δ = b2-4ac
Δ = -122-4·4·(-1147)
Δ = 18496
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{18496}=136$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-136}{2*4}=\frac{-124}{8} =-15+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+136}{2*4}=\frac{148}{8} =18+1/2 $
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